Senator Bob Menendez (D-New Jersey) and his wife, Nadine, have now been charged with bribery.
In addition, Federal prosecutors reportedly announced the charges on Friday and stated that during a search of the senator’s residence, they discovered $100,000 in gold bars and $480,000 in concealed currency.
The indictment alleges that Menendez and his wife consented to accept hundreds of thousands of dollars in bribes in exchange for protecting three New Jersey businessmen, Wael “Will” Hana, Jose Uribe, and Fred Daibes, and benefiting Egypt.
According to the filing, Menendez used his position as senator to profit Hana and the Egyptian government. Menendez provided sensitive U.S. government information and “took other steps that secretly aided the Government of Egypt.”
In addition, the court determined that Menendez promised to obstruct a criminal investigation and prosecution related to Uribe, and that the senator recommended that President Biden’s nominee for U.S. Attorney for New Jersey be someone “who Menendez believed could be influenced by Menendez” regarding prosecution of Daibes.
FBI agents implemented search warrants on Menendez’s residence in June 2022 and discovered more than $480,000 in cash.
The agents discovered envelopes of currency within Menendez-branded jackets.
Their investigation uncovered home furnishings, a luxury vehicle, and gold bars that were all supplied by the executives.
This is Menendez’s second indictment, which is unrelated to the previous allegation, which alleged that he accepted lavish gifts and campaign contributions from a Florida doctor in an effort to exert pressure on government officials.